Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Assume your line starts at zero, your first point is (-3,5) meaning your have a slope of 5/-3
[ f(x) = 5/-3x + b]
Answer:
Step-by-step explanation:
The applicable rules of exponents are ...
Your ratio simplifies to ...
_____
Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))
If one raw contains 3x-2 trees & if the total trees in the rectangle are 24x-16, that means Horizontal Rows x Vertical Rows =Total number of trees:
(3x-2) * Vertical Rows = 24x-16 ===> Vertical Rows =(24x-16) / (3x-2)
Perform the division & you will find Vertical Rows =8
