3 years ago

7) A baker had eighteen boxes for

Mathematics

1 answer:

Softa [21]3 years ago

8 0

Answer:

Step-by-step explanation:

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Tony had 2/3 of a pound of strawberries. Tony let his friend Larry eat 3/8 of the strawberries. How many pounds of strawberries

NARA [144]

Answer:

B) 1/4

Step-by-step explanation:

2/3lb of Strawberries. His friend at 3/8 of them so that would be 3/8 * 2/3 = 6/24 = 1/4. He ate 1/4lb of the strawberries

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3 years ago

Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form? thank you! :)

sukhopar [10]

Answer:

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

Step-by-step explanation:

$x=2-3\cos(t)$

$y=1+4\sin(t)$

Let's solve for $\cos(t)$ in the first equation and then solve for $\sin(t)$ in the second equation.

I will then use the following identity to get right of the parameter, $t$ :

$\cos^2(t)+\sin^2(t)=1$ (Pythagorean Identity).

Let's begin with $x=2-3\cos(t)$ .

Subtract 2 on both sides:

$x-2=-3\cos(t)$

Divide both sides by -3:

$\frac{x-2}{-3}=\cos(t)$

Now time for the second equation, $y=1+4\sin(t)$ .

Subtract 1 on both sides:

$y-1=4\sin(t)$

Divide both sides by 4:

$\frac{y-1}{4}=\sin(t)$

Now let's plug it into our Pythagorean Identity:

$\cos^2(t)+\sin^2(t)=1$

$\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1$

$\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1$

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

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x=y-4 is x=y-4

y=2+ 2x/2

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How to find the sides of a 30 60 90 triangle?

Sever21 [200]

All you need to do is plug in the numbers and you'll get the sides.

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