How many solutions does this system have?

You are going to visit a relative out of town and want to go to the gym while visiting. Hunkey Heros charges a registration fee

iragen [17]

The number of months when the gyms cost the same is 5 months.

<h3>When would the cost be the same?</h3>

Total cost of joining the gym = registration fee + (cost per month x number of months)

Hunkey Heros = $50 + $20m
Zipity-zapity- zap-that-fat = $70 + $10m

When the gyms costs are the same, the two above equations would be equal to each other:

50 + 20m = 70 + 10m

20m - 10m = 70 - 20

10m = 50

m = 50 / 10

m = 5

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4 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

What is the exact volume of a cylinder whose radius is 21 centimeters and whose height is 30 centimeters?

olga nikolaevna [1]

Volume of cylinder
v = πr²
v = 22/7 x 21²
v = 1385.441 cm³

4 0

3 years ago

Find the first term of the following geometric sequence ----,42,126,378,1,134

sergey [27]

Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...

126/42=378/126=1134/378=3

The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:

42=a(3)^(2-1)

42=3a

a=14

So the first term is 14.

8 0

3 years ago

8p+8=10+7p what is the solution set

Evgesh-ka [11]

The answer is: "p = 2" .
______________________________________________________
Explanation:
______________________________________________________
Given:
______________________________________________________
" 8p + 8 = 10 + 7p " ; Solve for "p" ;

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p <span>− 8 ;
</span>
to get:
_________________________________________
"p = 2 " ; which is our answer.
_________________________________________

8 0

3 years ago

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