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3 years ago

Which equation contains the points (-1,-8) and (3,4)

Mathematics

1 answer:

katrin [286]3 years ago

8 0

Answer:

y = 3x –5

Step-by-step explanation:

for slope-intercept form, y = mx + b

find the slope, m

(-8 -4)/(-1-3) = m

-12/-4 =m

3 = m

Substitute for m and use either coordinate for y and x to calculate b

4 = 3(3) + b

4 = 9 + b. Subtract 9 from both sides

4 –9 = b

–5 = b. Rewrite the equation with the calculated values for m and b

y = 3x –5

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Evaluate the function

NikAS [45]

Answer:

f = 9.25 (I think but maybe I read f(4) wrong)

Step-by-step explanation:

so f(4) means x = 4.

The new equation is

f(4) = 2x4 ^2 - 4 + 9
you first do 2x4^2. The minus 4. The add 9.
the answer to that is 4f = 37

Then solve

F = 9.25

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2 years ago

The sum of three consecutive terms of an A.P is 18 and their product is 120. Find the terms?

GarryVolchara [31]

Answer:

2 6 10

Step-by-step explanation:

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3 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

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3 years ago

Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A sandwich costs $2, and hot

Morgarella [4.7K]

A. Solution set is in the attachment (dark green shading in the middle)

B. Yes, 2(5) + 3(1) ≤ 15; 13 is less than or equal to 15

5 + 1 > 3, 6 is greater than 3

C. (4, 2) means that he buys 4 sandwiches and 2 hot lunches

7 0

3 years ago

The table below represents a function.

skelet666 [1.2K]

Answer:

i am pretty sure it is A/the graph is a straight line that has a slope of 6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers