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olga nikolaevna [1]
2 years ago
15

Scarly bought 3 pounds of cashews. Each pound of cashews cost $2.98. She paid with a $20 bill. How much change did Scarly get ba

ck?
Mathematics
2 answers:
pantera1 [17]2 years ago
7 0

Answer:

Answer:

Part a) Mr. Paul bought 14 oz of cashews

Part b) Mr. Paul bought 12 oz of walnuts

Part c) Mr Paul bought 2 oz more of cashews than walnuts

Part d) Mr Paul bought 2 more ounces of nuts than Mrs Toombs

Step-by-step explanation:

Part a) How many ounces of cashews did Mr. Paul buy?

Remember that

To convert lb to oz multiply by 16

we know that

Mr. Paul bought 7/8 lb of cashews <em> I think hope this helps:)</em>

Step-by-step explanation:

algol [13]2 years ago
5 0

Answer:

11.06

Step-by-step explanation

2.98*3=8.94

20-8.94= 11.06

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Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

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  • Length of XY = 6

<em><u>Recall:</u></em>

  • A line that divides a segment into two equal parts is referred to as segment bisector.

In the diagram attached below, line n divides XY into XM and MY.

Thus, the segment bisector of XY is: line n.

<em><u>Find the value of x:</u></em>

XM = MY (congruent segments)

  • Substitute

5x + 8 = 9x + 12

  • Collect like terms and solve for x

5x + 8 = 9x + 12\\5x - 9x = -8 + 12\\\\-4x = 4\\\\x = -1

XY = XM + MY

XY = 5x + 8 + 9x + 12

  • Plug in the value of x

XY = 5(-1) + 8 + 9(-1) + 12\\\\XY = -5 + 8 -9 + 12\\\\\mathbf{XY = 6}

Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

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A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0
3 years ago
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