Use a graph to solve the equation. Check your solution.

Aleks04 [339]

Answer:

Width is 24, length is 40

Step-by-step explanation:

64 can be split into 8 groups of 8, and the 8 groups can be split into 3 and 5. Then, take 3 x 8 for the width and 5 x 8 for the length, and you have the answer! I wish to you best of luck!

4 0

2 years ago

Which of the following represents "The sum of the abscissa and the ordinate is six"

ddd [48]

Answer:

The correct option: <u>x + y = 6 </u>

Step-by-step explanation:

In a Cartesian system or a coordinate system, the abscissa is the value of the horizontal (x) value and the ordinate is the value of the vertical (y) value.

So, The sum of the abscissa and the ordinate = x + y when written as an algebraic expression.

Since given that The sum of the abscissa and the ordinate is six

So, the correct equation is x + y = 6

7 0

4 years ago

Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(

andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

$v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}$

Where:

$x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval$

a. Let's find h(3) and h(4) using the data provided by the problem:

$h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f$

The average velocity over the interval [3, 4] is :

$v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s$

b. Let's find h(3.5) using the data provided by the problem:

$h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f$

The average velocity over the interval [3, 3.5] is :

$v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s$

c. Let's find h(3.1) using the data provided by the problem:

$h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f$

The average velocity over the interval [3, 3.1] is :

$v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s$

d. Let's find h(3.01) using the data provided by the problem:

$h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f$

The average velocity over the interval [3, 3.01] is :

$v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s$

e. Let's find h(3.001) using the data provided by the problem:

$h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f$

$v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s$

7 0

3 years ago

PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION QUICK!! The picture of the question is down below.

elena-s [515]

Answer:

1. 2 -- x-axis represents time, each vertical line represents 2 hours. (8 lines, 16 hours total)

2. 10 --- y-axis represents number of customers. (5 lines, 52 customers total. points go just above 5th line)

hope this helps :)

5 0

3 years ago

The compound probability of two events, E and F, is ; the probability of E is and of F is . In two or more complete sentences, e

lorasvet [3.4K]

Answer:

Events E and F are not independent if the probability of event E occurring is affecting the probability of event F occurring.

Step-by-step explanation:

Two events are independent when the probability of one event occurring has no connection with that of the other event.

Example, when you toss a coin and roll a six sided die, the probability of getting a head or a tail has no connection with the probability of getting any number face.A real life example will be the probability going to the mall and owning a cat at home.These two have no influence on one another.

Mathematically independent events can be calculated as;

P(E∩F)=P(E)-P(F)

3 0

3 years ago