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Whitepunk [10]
2 years ago
11

Service Pro Corp (SPC) is preparing adjustments for its September 30 year- end. For the following transactions and events, show

the September 30 adjusting entries that SPC would make
a. Prepaid Insurance shows a balance of zero at September 30, but Insurance Expense shows a debit balance of $2,340, representing the cost of a three-year fire insurance policy purchased on September 1 of the current year.
b. On August 31 of this year, Cash was debited and Service Revenue was credited for $ 1,500. The $ 1,500 related to fees for a three- month period beginning September 1 of the current year.
c. The company’s income tax rate is 20%. After making the above adjustments, SPC’s net income before tax is $ 10,000. No income tax has been paid or recorded.
Business
1 answer:
Gelneren [198K]2 years ago
3 0

Answer:

1 . Dr Prepaid Insurance $2,275

Cr Insurance Expense $2,275

2. Dr Service Revenue $1,000

Cr Deferred Revenue $1,000

3. Dr Income Tax Expense $2,000

Cr Income Tax Payable $2,000

Explanation:

Preparation of the journal entries

1 . Dr Prepaid Insurance $2,275

Cr Insurance Expense $2,275

($2,340 - $2,340 × 1 months ÷ 36 months

= $2,340 - $65

= $2,275)

2. Dr Service Revenue $1,000

Cr Deferred Revenue $1,000

($ 1,500 × 2 months ÷ 3 months

= $1,000)

3. Dr Income Tax Expense $2,000

Cr Income Tax Payable $2,000

(.20*$10,000)

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Answer:

285,000 common stock outstanding with a $8 par value

it declares 13% stock dividend

market price at $16

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3 0
3 years ago
A 60,000 square meter rectangular yard is to be enclosed on three sides by wood fencing that costs $25.00 per meter and on the f
raketka [301]

Answer:

C'(y) = 50 -\frac{3900000}{y^2}=0

And we can solve for y and we got:

y = \sqrt{\frac{3900000}{50}}= 279.285

And using condition (1) we can solve for x and we got:

x= \frac{60000}{279.285}= 214.834

So then the minimum cost for this case would be:

C = 50*279.285 + 65*214.834 = 27928.49

Explanation:

For this case the graph attached illustrate the problem for this case

We know that the total area is 60000, so then we have:

xy = 60000

If we solve for x we got:

x = \frac{60000}{y}  (1)

Now we can define the cost function like this:

C = 2*(25)*y + 25 x +40 x

C(x,y) = 50 y + 65 x

We can use the condition (1) and if we replace in the cost function we have:

C(y) = 50 y + 65(\frac{60000}{y})

Since we need to minimize the cost, we can derivate the function in terms of y and we got:

C'(y) = 50 -\frac{3900000}{y^2}=0

And we can solve for y and we got:

y = \sqrt{\frac{3900000}{50}}= 279.285

And using condition (1) we can solve for x and we got:

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So then the minimum cost for this case would be:

C = 50*279.285 + 65*214.834 = 27928.49

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Yakvenalex [24]

Answer:

0.0084

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to use the table, we will have to compute a certain value

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Probability he has worked in the store for over 10 years can be obtained by taking the z value of 2.39 to the normal probability distribution table to read off the values.

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We subtract the value obtained from the table from 1 to get the probability required.

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