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n200080 [17]
3 years ago
9

What is the surface area of the figure shown? (Use 3.14 for π.)

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0
We know that
Part 1) 
[surface area of a cone without base]=<span>π*r*l
r=3 in
l=slant height ----> 6 in
</span>[surface area of a cone without base]=π*3*6------> 56.52 in²

[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²

[surface area of the composite figure]=56.52+122.46-----> 178.98 in²

the answer Part A) is
 178.98 in²

Part B) 
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²

the answer Part B) is 
 932 ft²



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In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C
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Answer:

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

Step-by-step explanation:

<em>Step(i)</em>:-

<em>Given sample size 'n' =300</em>

Given data  random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

<em>Given sample proportion </em>

<em>                        </em>p^{-}  = \frac{x}{n} = \frac{182}{300} =0.606

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

<em>90% confidence interval for the proportion is determined by</em>

(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} }  , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })

(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} }  ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })

(0.6066 -  0.0463  ,0.6066 +  0.0463)

(0.5603,0.6529)

<u>final answer</u>:-

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

5 0
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3. Bob the Builder wants to earn an annual rate of 10% on his investments,
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Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

T = E + P

In this question:

Rate of 10%, so I = 0.1.

9 months, so t = \frac{9}{12} = 0.75

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

T = E + P

3000 = E + P

E = 3000 - P

Then

E = P*I*t

3000 - P = P*0.1*0.75

1.075P = 3000

P = \frac{3000}{1.075}

P = 2790.7

He should pay $2,790.7.

8 0
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