Question

What is the surface area of the figure shown? (Use 3.14 for π.)

Answer 1

We know that
Part 1) 
[surface area of a cone without base]=π*r*l
r=3 in
l=slant height ----> 6 in
[surface area of a cone without base]=π*3*6------> 56.52 in²

[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²

[surface area of the composite figure]=56.52+122.46-----> 178.98 in²

the answer Part A) is
 178.98 in²

Part B) 
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²

the answer Part B) is 
 932 ft²