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3 years ago

9

What is the surface area of the figure shown? (Use 3.14 for π.)

1 answer:

Ivanshal [37]3 years ago

4 0

We know that
Part 1)
[surface area of a cone without base]=<span>π*r*l
r=3 in
l=slant height ----> 6 in
</span>[surface area of a cone without base]=π*3*6------> 56.52 in²

[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²

[surface area of the composite figure]=56.52+122.46-----> 178.98 in²

the answer Part A) is
178.98 in²

Part B)
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²

the answer Part B) is
932 ft²

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Step-by-step explanation:

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$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

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