Hmmm well may I ask what your doing with the shapes bc um well if you put them shapes in the circle/oval why is it hard? I don’t do this stuff I’m confused...
Answer:
x=2
Step-by-step explanation:
use distributive property: x^2+2x-1=4
remove the -1 by adding 1 on both sides: x^2+2x=5
use the guadratic fromula: ax²+bx+c=0
plug in the equation x^2+2x-5=0
a,b and c are the coefficients to plug into the formula
a=1, b=2, c=-1
Finally, you will find that x=2
Answer:
256
Step-by-step explanation:
A calculator works well for this.
_____
None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.
1 to any power is still 1, so the factors (1^n) can be ignored.
After you ignore all of the things that can be ignored, your problem simplifies to ...
(2^2)(2^-3)^-2
The rules of exponents applicable to this are ...
(a^b)^c = a^(b·c)
(a^b)(a^c) = a^(b+c)
Then your product simplifies to ...
(2^2)(2^((-3)(-2)) = (2^2)(2^6)
= 2^(2+6)
= 2^8 = 256
Answer:
1 5/18
one and five eighteenths
Step-by-step explanation: