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NISA [10]
3 years ago
7

PLZ HELP me with this and i will elect brainliest winne i promise just look at the photo and tell me what to do plz.

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
You could use math in food
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(8.1 x 10-3). (3 x 109)
mihalych1998 [28]
your answer for this is 18,540.9
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4 years ago
Simplify 3a - 2(8 +4a)
tigry1 [53]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Let's simplify step-by-step.

3a − 2 ( 8 + 4a )

Distribute:

= 3a + ( −2 ) ( 8 ) + ( −2 ) ( 4a )

= 3a + −16 + −8a

Combine Like Terms:

= 3a + −16 + −8a

= ( 3a + −8a ) + ( −16 )

Answer:

= −5a − 16

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

4 0
3 years ago
The price of an all-access ticket to the fair is $42.99 before tax. Roland bought the all-access ticket for 40% off. He then pai
Ulleksa [173]

Answer:

18.39972

Step-by-step explanation:

40% of 42.99 is 17.196

plus a 7% of sales tax would be 18.39972

5 0
4 years ago
Read 2 more answers
Rosters Chicken advertises​ "lite" chicken with​ 30% fewer calories than standard chicken. When the process for​ "lite" chicken
ella [17]

Correct question is;

Rosters Chicken advertises "lite" chicken with 30% fewer calories than standard chicken. When the process for "lite" chicken breast production is in control, the average chicken breast contains 450 calories, and the standard deviation in caloric content of the chicken breast population is 20 calories. Rosters wants to design an X-chart to monitor the caloric content of chicken breasts, where 25 chicken breasts would be chosen at random to form each sample. a) What are the lower and upper control limits for this chart if these limits are chosen to be four standard deviations from the target? b) What are the limits with three standard deviations from the target? Upper Control Limit (UCL)calories (enter your response as an integer).

Answer:

A)UCL = 466

LCL = 434

B)UCL = 462

LCL = 438

Step-by-step explanation:

We are given;

Mean;μ = 450

Standard deviation; σ = 20

Sample size; n = 25

A) We are told that these limits are chosen to be four standard deviations from the target.. This means that z-value = 4.

Thus, upper control limit will be the formula;

UCL = μ + 4σ/√n

UCL = 450 + 4(20)/√25

UCL = 450 + 16

UCL = 466

Lower control limit will be;

LCL = μ - 4σ/√n

LCL = 450 - 4(20)/√25

LCL = 450 - 16

LCL = 434

B) We are now told that these limits are chosen to be three standard deviations from the target.

Thus, z = 3

So;

UCL = μ + 3σ/√n

UCL = 450 + 3(20)/√25

UCL = 450 + 12

UCL = 462

Lower control limit will be;

LCL = μ - 3σ/√n

LCL = 450 - 3(20)/√25

LCL = 450 - 12

LCL = 438

8 0
4 years ago
What is the equation in point-slope form of a line that passes through the points (−4, −1) and (5, 7) ? y+1=87(x+4) y+4=98(x+1)
Vitek1552 [10]
I think its 4+(-98=y)
6 0
3 years ago
Read 2 more answers
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