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Nikolay [14]
3 years ago
11

The number or variable for 5 is the number 4, and there’s a negative sign in between. For the parentheses in front of the 6 ther

e is a negative sign. Could someone help me answer this problem ?

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

Answer:

11x^4

Step-by-step explanation:

The double negative automatically makes something positive. Your new expression is 5x^4 + 6x^4.

The only other thing you need to do is combine like terms by adding them together.

11x^4

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7 0
4 years ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

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3 years ago
Find the product<br> 876 greater or equal to 65 =
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Greater ..............
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3 years ago
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kirill [66]

Answer:

y = -4/3x - 1

Step-by-step explanation:

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3 years ago
Three moons are in the same circular orbit around a planet. The moons are each 120,000 kilometers from the surface of the planet
VladimirAG [237]

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

MN is the diameter of the planet which is MN = 60000

AM and NC are the distance of moons from the surface of the planet.

AM = NC = 120000

Since, angle ABC is given as 90 degree, it means, line AC will pass from the diameter of the planet.

So, distance between moon A and moon C is =

AC=AM + MN + NC

AC = 120000+ 60000+ 120000

AC = 300000

Hence the distance between point A and point C is 300000 Km.   :   Answer

Hope it will help :)

8 0
3 years ago
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