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defon
3 years ago
13

Consider the image that shows a tower anchored by a guy with the guy wire is attached at point b on the tower 119 feet above the

ground and then anchored to the ground at point a 120 feet from the base of the tower.
Options are: A) sin0= 119/120, B) sin0= 120/119, C) sin0= 119/169, and D) sin0= 120/169

Mathematics
2 answers:
zhenek [66]3 years ago
8 0

Answer:

119/169

Step-by-step explanation:

liq [111]3 years ago
3 0

Answer:

sin0 = 119/169

Step-by-step explanation:

In trigonometry, the formula for sine is opposite/hypotenuse

To find the opposite, you find the angle and look what is right across from it. In this case 119 is right across from the angle.

And of course, our hypotenuse is 169.

Therefore, your answer is

Sin0 = 119/169

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A ski gondola carries skiers to the top of a mountain. assume that weights of skiers are normally distributed with a mean of 199
Allushta [10]
A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb

</span>B)  First, find the z-score:
z = (value - mean) / stdev
   = (150 - 199) / 41
   = -1.20

We need to find P(z > -1.20) = 1 - P(z < -1.20)

Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849

Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>

C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb

Let's repeat the steps of point B)

z = (187.5 - 199) / 41
   = -0.29

P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141

</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%

D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
                                     = 3750 </span></span><span>÷ 199
                                     = 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
4 0
3 years ago
Here is an addition sentence.
kiruha [24]

Answer: B. 3+(1+11)=15


Step-by-step explanation:

1. By definition, the associative property of addition is:

(a+b)+c=a+(b+c)

2. Therefore, if you have the following expression:

(3+1)+11=15

You apply  the Asociative property of addition by regrouping the numbers as following:

3+(1+11)=15

3. Then, you can conclude that the correct option is B.

4 0
4 years ago
Peter is twice the age of Sara. If their total age is 27 years. how old is Sara?
Xelga [282]

Answer:

Just do 27x2 bro simple as that

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Name the line and plane shown in the diagram. A.AB and plane ABD B.BA and plane DC C.AC and plane ABD D.AB and plane DA
elena-14-01-66 [18.8K]

Answer: The line is AB and the plane is ABD, the first option is the correct one.

Step-by-step explanation:

Ok, first some definitions.

A line is any line that crosses two colinear points. Particularly, you can see in the graph that the line crosses through A and B, so the line is AB.

A plane needs 3 non-colinear points (if the points where colinear, then the points may define a line). Other definition of plane is "a line and a point that is not in the line"

So, if our line is AB, then the possible planes are:

ABC and ABD.

then the correct option is:

Line AB and plane ABD, so the correct option is the first one.

6 0
3 years ago
A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
professor190 [17]

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0
3 years ago
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