Hello user
To solve for V we simplify both sides of the equation then isolate the variable to get v <span>≥ 2
Therefor the answer is: </span>v ≥ 2
<span>
I hope this helped
-Chris</span>
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Given:
Volume of a cube = 27,000 in^3
(Note: A cube has equal sides)
The volume of a cube = a^3
So,
![\begin{gathered} 27000=a^3 \\ \sqrt[3]{27000}\text{ = a} \\ a\text{ = 30 in.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2027000%3Da%5E3%20%5C%5C%20%5Csqrt%5B3%5D%7B27000%7D%5Ctext%7B%20%3D%20a%7D%20%5C%5C%20a%5Ctext%7B%20%3D%2030%20in.%7D%20%5Cend%7Bgathered%7D)
Therefore, the lenght of one side is 30 inches.
Answer:
6
Step-by-step explanation:
Because 6/3 equals 2