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olga_2 [115]
3 years ago
10

4(x+2)-12=3(x-2) solve for x

Mathematics
1 answer:
aalyn [17]3 years ago
6 0

Answer:

x= -2

Step-by-step explanation:

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How many gallons of a 50% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 40% antif
Mariulka [41]

I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.

Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.

Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.

We want the concentration of antifreeze to be 40% in the new solution, so we need to have

(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4

Solve for <em>x</em> :

0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)

0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24

0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18

0.1 <em>x</em> = 6

<em>x</em> = 6/0.1 = 60 gal

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=7%284%20%2B%20x%29%20%3D%204%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="7(4 + x) = 4 {}^{2
Annette [7]
28 + 7x = 16
7x = 16-28=-12
x = -12/7 Answer
6 0
3 years ago
A typical middle-income household in 1980 earned $34,757. A similar household in 2009 earned $38,550. What was the relative incr
S_A_V [24]

Given conditions are :

In 1980's, a typical middle-income household earned=  $34,757

In 2009, a similar middle-income household earned= $38,550

And we have to find relative increase in income for these households from 1980 to 2009.

So first we will find the total increase in amounts.

38550-34757=3793

Relative increase = \frac{3793}{34757}*100

= 10.91% or rounding it off we get approx 11%.

Hence, the answer is 11%.

5 0
3 years ago
Read 2 more answers
Type the correct answer in each box
Luba_88 [7]

Answer:

We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

5 0
3 years ago
Can someone please help me with this!?!?!
lys-0071 [83]
They are congruent because of the angles, which means the congruency reason should be SAS.
4 0
3 years ago
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