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3 years ago

A grocery store recently sold several cans of soup.

Mathematics

1 answer:

Licemer1 [7]3 years ago

4 0

Answer:

21/60

Step-by-step explanation:

32 + 1 + 3 + 3 + 21 = 60

ans = 21/60

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Please help me!!!!!!!!!!!

shutvik [7]

The given parabola is $y+4=12(x-7)^2$ . Compare with the standard equation of a parabola in vertex form, $y-c=a(x-b)^2$ .

The vertex of this parabola is $(b,c)$ . Compare $y+4=12(x-7)^2$ with the standard equation $y-c=a(x-b)^2$ .

we see $c=-4,b=7$ . Thus, the vertex of the given parabola is $(7,-4)$ .

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4 years ago

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A pet store has 5 tanks of fish. Each tank has the same number of fish. The store has 50 fish total. How many fish are in each t

Romashka-Z-Leto [24]

answer : 10 fish in each tank because 10 time 5 equals 50 and there 5 tanks sotaht mean 50 divided by 5 it will be 10 fish

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3 years ago

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Anna bought a skirt on sale at a clothing store for $54.48. The original price of this skirt was $72.64. She is interested in a

Basile [38]

$115.45 This should be the correct answer. Hope this help need brainlest.

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4 years ago

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Galen sold tickets for his church’s carnival for a total of $2,820. Children’s tickets cost $3 each and adult tickets cost $5 ea

Veronika [31]

Answer:

a = 195 ; c = 615

Step-by-step explanation:

So, you want to start by forming your equations...

I will use 'c' for children and 'a' for adults for my variables

3a + 30 = c

(this is because of the info that 30 more tickets than 3 times the amount of children's were sold than adult)

then for equation 2:

3c + 5a = 2820

(this is because of the prices of the tickets and the total money raised)

Then, plug in the equation for c

Your equation should look like:

3(3a + 30) + 5a = 2820

You get:

(9a +90) + 5a = 2820

Then:

14a = 2730

So:

a = 195 adult tickets sold

Plug in a, to find c:

3 (195) + 30 = c

585 + 30 = c

c = 615 children tickets sold

4 0

3 years ago

What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.

Lelu [443]

Check the picture below.

$\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}$

5 0

3 years ago