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2 years ago

Answer as soon as you can.

Mathematics

2 answers:

Lemur [1.5K]2 years ago

6 0

Answer: 24 cm squared

Step-by-step explanation:

The formula to find a triangle area is area = 0.5(base*height)

In this case, the base is A, (6) and the height is B, (8).

6*8=48

So we did the base*height. Now we need to divide it by 2.

48/2=24

Since it’s the area of something we must make it squared and since the units are centimeters we now have 24 cm squared as our final answer.

omeli [17]2 years ago

3 0

Answer:

Step-by-step explanation:

24cmsquare is the answer

vibhorpagare avatar

area of right angle triangle = ab/2 = 48/2 = 24

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Leona [35]

Answer:

That would be 2/3

Step-by-step explanation:

1/3 would be the first line after 0 and 3/3 is = to 1 so the correct answer is 2/3

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2 years ago

Read 2 more answers

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Alik [6]

Answer:

$d=28.28$

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

$a^{2} +b^{2} =c^{2}$ a is the height, b is the base, and c is

the hypotenuse.

To obtain the value of the hypotenuse

$c= \sqrt{a^{2} +b^{2} }$

To find the value of the lenght of the diagonal d across the square, we have:

$d=\sqrt{a^{2} +b^{2} }$ Where a = b = 20

Substituting the values

$d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284$

Round the answer to 2 decimal places

$d=28.28$

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2 years ago

Please teach me on how to answer this question. (addmath question)

arsen [322]

We know that $\overline{x}=8$ so:

$\overline{x}=8\\\\\\\dfrac{\sum\limits_{k=1}^7\,x_k}{7}=8\qquad|\cdot7\\\\\\ \boxed{\sum\limits_{k=1}^7\,x_k=56}$

We want to calculate:

$\sum\limits_{k=1}^7\,\big(2x_k-3\big)^2=\sum\limits_{k=1}^7\,\big(4x_k^2-12x_k+9\big)=\\\\\\=\sum\limits_{k=1}^7\,4x_k^2-\sum\limits_{k=1}^7\,\big12x_k+\sum\limits_{k=1}^7\,9=4\sum\limits_{k=1}^7\,x_k^2-12\sum\limits_{k=1}^7\,x_k+\sum\limits_{k=1}^7\,9=\\\\\\=4\cdot672-12\cdot56+7\cdot9=2688-672+63=\boxed{2079}$