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2 years ago

When the target number is rounded to the nearest million, the millions digit is 1.

Mathematics

1 answer:

Sladkaya [172]2 years ago

6 0

Answer:

185445

Step-by-step explanation:

am just guessing but plssssssss give me brainliest

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PLS HELP I NEED IT I will give u points

loris [4]

Answer:

15b

Step-by-step explanation:

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2 years ago

Can someone help me

Morgarella [4.7K]

The total cost would be $4,050. Hope this helps!

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3 years ago

Read 2 more answers

Find the inverse of the function y = 3x + 5 Find the inverse of the function y=3x+5

Viktor [21]

Answer:

First Inverse function= f^-1(x)=x/3-5/3

Second Inverse function=f^-1(x)=x/3-5/3

Step-by-step explanation:

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2 years ago

Over 1,000 people try to climb Mt. Everest every year. Of those who try to climb Everest, 31 percent succeed. The probability th

Anit [1.1K]

Answer:

A- 0.125

B- Success of climbing mount Everest is independent of age.

Step-by-step explanation:

Let x denote success in climbing Mount Everest

Let y denote the climber is at least 60 years old.

Therefore,

P(x) = 0.31

P(y) = 0.04

P( x ∩ y) = 0.005

Probability of success when the climber is at least 60 years old =

P( x ∩ y) ÷ P(y) = 0.005 ÷ 0.04 = 0.125.

The success rate is independent of age as there are both success and failure rates across board on the scale of ages of climbers.

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3 years ago

Jeremy analyses one of his parachute jumps. He draws a graph showing his velocity up to the opening of his parachute. a) Estimat

jeyben [28]

Answer:

Jeremy's acceleration is about $1\,\frac{m}{s^2}$ at t =10 s

His average speed is about 44.5 m/s in this section of his jump approximating with points on the curve (under-estimate)

His average speed is about 46 m/s if using the tangent line (over estimate)

Step-by-step explanation:

Jeremy's acceleration can be estimated by the curve's derivative at that point. That is the slope of the tangent line to the velocity curve at x = 10 sec. Please see attached image where the tangent line is drawn in orange, and the points to use to calculate its slope are drawn in green.

These points are : (6, 42) and (14,50) which using the slope formula give:

$slope=\frac{y_2-y_1}{x_2-x_1}= \frac{50-42}{14-6}=\frac{8}{8} \frac{m}{s^2} = 1\,\frac{m}{s^2}$

So his acceleration at that point is about $1\,\frac{m}{s^2}$

Now, using about the same interval of x-values (from 6 to 14), the corresponding speeds are approximately: 40 (for time 6 seconds) and 49 (for time 14 seconds (look for the red dots on the attached image). Since the average velocity is given by the integral of the function between those points divided by the length of the interval where it is calculated:

$v_{average}=\frac{area}{interval\,\,length}$

and we don't have the actual velocity function to estimate the integral, we can approximate this area by that of a trapezoid that connects the red dots with the bottom of the horizontal axis (see red trapezoid in the image). Clearly from the image, this approximation would give us an under-estimate of the actual average speed.

The area of this trapezoid is: approximately:

$Trapezoid\,\, area=(49+40)\,8/2=356$

Then the average velocity estimated from it is:

$v_{average}=\frac{356}{8} \frac{m}{s} =44.5\,\frac{m}{s}$

If the area is approximated instead with the trapezoid form by the green points we used to calculate the acceleration (this would give us an over-estimate):

$Trapezoid\,\, area=(50+42)\,8/2=368$

Then the average velocity estimated from it is:

$v_{average}=\frac{368}{8} \frac{m}{s} =46\,\frac{m}{s}$

while his actual instantaneous velocity seems to be about 46 m/s from the graph

4 0

3 years ago