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seraphim [82]
2 years ago
6

How do I solve 6a + 5a = −11

Mathematics
2 answers:
SashulF [63]2 years ago
5 0

Answer:

a = - 1

Step-by-step explanation:

Step 1:

6a + 5a = - 11        Equation

Step 2:

11a = - 11         Combine Like Terms

Step 3:

a = - 11 ÷ 11       Divide

Answer:

a = - 1

Hope This Helps :)

g100num [7]2 years ago
4 0

Answer:

a= -1

Step-by-step explanation:

First you combine like terms which in this equation is 6a and 5a. so, 5 + 6 is 11 so you get 11a. Then just move the equal sign over and do nothing with the -11.

PLEASE MARK BRAINLIEST

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Step-by-step explanation:

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HELP 1x3 divided by 56 then multiply that by 9
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Answer:

0.48

Step-by-step explanation:

1x3/56 then multiply it by 9

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3 years ago
Nick planted a cedar tree. It grew 10 cm in ½ of a year. What will the height of the tree be at the end of 6 years?
user100 [1]

Answer:

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Step-by-step explanation:

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2 years ago
Please help me ASAP! Triangle ABC is located at A (2, 3), B (4, 4), and C (6, 3). Zackary says that triangle ABC is an isosceles
son4ous [18]
<h2>Hello!</h2>

The answer is:

The second option,

Zackery, because AB=BC

<h2>Why?</h2>

To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.

So, finding the distances we have:

From A to B: (2,3) and (4,4)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

From B to C: (4,4) and (6,3)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:

Zackery, because AB=BC

Have a nice day!

7 0
2 years ago
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