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seraphim [82]
3 years ago
6

How do I solve 6a + 5a = −11

Mathematics
2 answers:
SashulF [63]3 years ago
5 0

Answer:

a = - 1

Step-by-step explanation:

Step 1:

6a + 5a = - 11        Equation

Step 2:

11a = - 11         Combine Like Terms

Step 3:

a = - 11 ÷ 11       Divide

Answer:

a = - 1

Hope This Helps :)

g100num [7]3 years ago
4 0

Answer:

a= -1

Step-by-step explanation:

First you combine like terms which in this equation is 6a and 5a. so, 5 + 6 is 11 so you get 11a. Then just move the equal sign over and do nothing with the -11.

PLEASE MARK BRAINLIEST

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Have a great night! Hope this helped!

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3 years ago
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3 years ago
The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

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Step-by-step explanation:

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