1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
We can first turn the text into a proper formula:
x plus 10 plus 6 x plus 2 x
x+10+6x+2x
The like terms are the numbers with
We can then put the like terms together to continue the calculation:
x+6x+2x+10
=9x + 10
Therefore, the answer is 9x + 10.
Hope it helps!
D (-4 , -1)
relflected over x-axis= (4 , 1)
180 degrees= (-4 , -1)
She’ll have to make 4 more stitches in order to get 6 good ones. Each time she creates 3 she undoes 2 which after 4 more times would leave her with 6 good stitches.
