Question

Please help, would be grateful :)

Answer 1

Answer:

$\frac{4}{3x-4}$

Step-by-step explanation:

The first thing we do to solve this is factor is completley

You can factor out a 4 from the numerator and get

4(3x+4)

The denominator is a  difference of squares which means that

(x^2-y^2)=(x-y)(x+y)

which means that 9x^2-16=

(3x-4)(3x+4)

Put these together and get

$\frac{4(3x+4)}{(3x-4)*(3x+4)}$

The 3x+4 cancels out and we get left with

$\frac{4}{3x-4}$

Answer 2

4/3x-4 I think I’m not fully sure