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astraxan [27]
2 years ago
11

Please help, would be grateful :)

Mathematics
2 answers:
Alborosie2 years ago
5 0

Answer:

\frac{4}{3x-4}

Step-by-step explanation:

The first thing we do to solve this is factor is completley

You can factor out a 4 from the numerator and get

4(3x+4)

The denominator is a  difference of squares which means that

(x^2-y^2)=(x-y)(x+y)

which means that 9x^2-16=

(3x-4)(3x+4)

Put these together and get

\frac{4(3x+4)}{(3x-4)*(3x+4)}

The 3x+4 cancels out and we get left with

\frac{4}{3x-4}

Black_prince [1.1K]2 years ago
5 0
4/3x-4 I think I’m not fully sure
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Simplify using only POSITIVE exponents:
pickupchik [31]

So here are a few rules with exponents that you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: x^m\div x^n=x^{m-n}
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<h2>1.</h2>

Firstly, solve the outside exponent:

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Next, convert the negative exponents into positive ones:

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<h2>2.</h2>

For this, just divide:

\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3

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<h2>3.</h2>

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<u>Your final answer is \frac{t^4}{r^7b^8w}</u>

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