That sir would be I think its y=mx+b
If this is not a typo, and you mean 15.16 as in 15 and 16 hundredths, we can express this into a mixed number.
Mixed numbers are a whole number with the remainder of that number as a fraction.
For example, 1.25 as a decimal = 1 1/4 as a mixed number.
Since we already have our whole number, 15, we need to know what 16 hundredths is simplified as a fraction.
Currently, our mixed number is 15 16/100.
To simplify this, we need to find a common factor that 16 and 100 share.
Since they are both even numbers, let's divide by 2.
16/2 = 8
100/2 = 50.
Our new mixed number is 15 8/50.
Currently our fraction is still even, so divide by 2 again.
8/2 = 4
50/2 = 25
Your new mixed number is 15 4/25.
4 and 25 have no common factors, so the fraction is simplified.
Your answer is:
15.16 is 15 4/25 as a mixed number.
I hope this helps!
The expression which represents the perimeter, in centimeters, of the rectangle is; (18d +10f) centimetres.
<h3>Perimeter of a rectangle</h3>
Since the perimeter of a rectangle is given by the formula;
In essence, Perimeter, P = 2(2d – 3f) + 2(7d + 8f)
Ultimately, the perimeter of the rectangle is; (18d +10f) centimetres.
Read more on perimeter of a rectangle;
brainly.com/question/17297081
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;


Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;



Thus, the length of the major arc ACB is 5.5π m
<h3>
Answer: Choice C</h3>
Work Shown:

So that's why the answer is choice C
The requirement that x is nonzero isn't technically necessary. The original expression simplifies to choice C even when x = 0 is the case. Also, we don't have issues such as division by zero errors that could arise. It's a bit curious why your teacher put in that condition.