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krok68 [10]
3 years ago
9

Look at the image below

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Step-by-step explanation:

hello!

(l*L *h)/3 =

(4*11* 9)/3 => 132 km³

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Find the volume of a right circular cone that has a height of 11.8 ft and a base with a radius of 16ft. Round your answer to the
Marina CMI [18]

Answer:

V = 3163.52 cubic foot

Step-by-step explanation:

The formula for volume of a right circular cone

v = πr^2 h/3

V = volume of the cone

π = pie

r = radius of the cone

h = height of the cone

We are provided with

Radius = 16ft

Height = 11.8ft

π - 22/7

Inserting the values

V = πr^2h/3

V = 22/7 * 16^2 * 11.8/3

V = 3.142 * 256 * 3.933

V = 3163.516416

According to the question, we are asked to round off to nearest tenth cubic foot

V = 3163.52 cubic foot

7 0
4 years ago
The average of manny's three tests is an 84. what must he get on a 4th test to raise his average to a 87
Alexeev081 [22]
(X+Y+Z)/3=84  X,Y,Z IS THE THREE UNKNOWN SCORES.TO KNOW THE TOTAL , MULTIPLY THE 84 BY 3.
84*3=252
(252+H)/4=87  H IS THE FOURTH GRADE HE SHOULD HE IF HE WANTS HIS AVERAGE TO BE 87
87*4=348
252+H=348
H=348-252
H=96

3 0
3 years ago
Let u and v be the solutions to 3x^2 + 5x + 7 = 0. Find u/v+v/u
Hitman42 [59]

Answer:   \dfrac{-17}{21}

Step-by-step explanation:

Given: u and v be are the solutions of  3x^2+5x+7=0

Let  ax^2+bx+c=0 is the quadratic equation and u and v are the zeroes/solutions then

Sum of zeroes;   u+v = \dfrac{-b}{a}

Product of zeroes; uv= \dfrac{c}{a}

Comparing  3x^2+5x+7=0  to  ax^2+bx+c=0

we get a= 3 , b= 5 and c = 7

u+v = \dfrac{-b}{a} = \dfrac{-5}{3}----(i)

uv= \dfrac{c}{a} = \dfrac{7}{3}----(ii)

Now we have to find

\dfrac{u}{v} +\dfrac{v}{u} =\dfrac{u^2+v^2}{uv} adding and subtracting 2uv in numerator we get

= \dfrac{u^2+v^2+2uv-2uv}{uv}= \dfrac{(u+v)^2-2uv}{uv}

Substituting the values from (i) and (ii) we get

\dfrac{(\dfrac{-5}{3} )^2-2\times \dfrac{7}{3} }{\dfrac{7}{3} } = \dfrac{\dfrac{25}{9} -\dfrac{14}{3} }{\dfrac{7}{3} }= \dfrac{\dfrac{25-42}{9} }{\dfrac{7}{3}} =\dfrac{-17}{9} \times \dfrac{3}{7} = \dfrac{-17}{21}

Hence, the value of \dfrac{u}{v} +\dfrac{v}{u}   is  \dfrac{-17}{21}

5 0
4 years ago
PLEASE HELP!!!!!!!!
jolli1 [7]
So hmm check the picture below

and since you already covered solving system of equations, surely you'll breeze right through B)

5 0
3 years ago
Any one show how to do this
vfiekz [6]
W is the X axis so as the X goes back to the origin, the line, H(w) gets larger.
8 0
4 years ago
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