Answer:
D. No, because group A is already the control group.
The vector equation of the line through the origin perpendicular to the plane is
.. (x, y, z) = t(2, 3, -1)
so the point of interest will satisfy
.. 2(2t) +3(3t) -(-t) = -3
.. 14t = -3
.. t = -3/14
and its coordinates are (x, y, z) = (-3/7, -9/14, 3/14)
Answer:
x = 5
Step-by-step explanation:
using the Pythagorean theorem:
(x-1)² + (x-2)² = x²
x²-2x+1 + x²-4x+4 = x²
reduce:
2x²-6x+5 = x²
subtract x² from each side:
x²-6x+5 = 0
(x-1)(x-5) = 0
x=1 but because shorter leg would be 0, a triangle would be impossible.
x=5
To do this problem, you will need to know the side lengths of the triangle. If you have those, just plug them in for a, b, and c and evaluate the square root.
Here is an example. If the sides are 3, 4, 5.
It would be:

The 6 is in the formula because it is the semi-perimeter (half).