Answer:
I believe the answer is 55 degrees.
Plz don't report me if i'm wrong.
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
f(x) = 4x^2 + 8x − 5
To find the x intercepts set y = 0
0 =4x^2 + 8x − 5
Factor
0=(2x-1)(2x+5)
Using the zero product property
2x-1 =0 2x+5 =0
2x=1 2x = -5
x = 1/2 x = -5/2
The x intercepts are ( 1/2 ,0) and ( -5/2,0)
Rewriting in vertex form by completing the square
4 ( x^2 + 2x) -5
4 ( x^2+2x +1) -4*1 -5
4 ( x+1) ^2 -9
Vertex form is
a( x-h) ^2 +k where ( h,k) is the vertex
The vertex is ( -1,-9)
We know it opens upwards since a > 0
Plot the vertex and the x intercepts
The graph is symmetric on based on the vertex
Answer:
8793
Step-by-step explanation:
Multiply and divide first, making the equation 8811-17-1. Now subtract. This leaves 8793
Answer:
Linearly, because the table shows that the sunflowers increased by the same amount each month
Step-by-step explanation:
Given the table

Note that months change one-by-one (21-1, 3-2=1, 4-3=1).
Also
![17.2-15=2.2\ [\text{from month 1 to month 2}]\\ \\19.4-17.2=2.2\ [\text{from month 2 to month 3}]\\ \\21.6-19.4=2.2\ [\text{from month 3 to month 4}]](https://tex.z-dn.net/?f=17.2-15%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%201%20to%20month%202%7D%5D%5C%5C%20%5C%5C19.4-17.2%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%202%20to%20month%203%7D%5D%5C%5C%20%5C%5C21.6-19.4%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%203%20to%20month%204%7D%5D)
This means the number of sunflowers increases linearly, because the table shows that the sunflowers increased by the same amount each month
Answer:
30
Step-by-step explanation:
To find the determinant of a 3x3 matrix, you can use this method. (See picture.)
Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.
Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.
det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]
det A = -2 (3)(-5) − 0 + 0
det A = 30