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abruzzese [7]
3 years ago
9

Elliot collects miniature toy cars. He wants to fill 4 display cases.each display case holds 15 cars. He has 28 cars now, and he

is able to buy 3 more every month with the money he saves from his allowance. How many more months will it be until elliot has enough cars to fill all 4 display cases?
Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

Elliot has to wait 11 months before he has enough cars

Step-by-step explanation:

Elliot has 4 display cases with each case being able to hold 15 cars. Thus we know

total # of cars Elliot can place in his display case = 4 * 15 = 60 cars

From this, we can figure out how many more cars Elliot needs by subtracting the amount of cars he already has

# of cars Elliot needs = 60 - 28 = 32 cars

Now to find the number of months Elliot needs, we divide by how many he can buy each month

# of months Elliot needs to save up for = 32 / 3 = 10 2/3

Assuming Elliot does not get his allowance until the end of the month, we will have to round the number of months up to the nearest integer, 11

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alexandr1967 [171]

Answer:

1/6

1/14

5/64

3/8

Step-by-step explanation:

Easiest and fastest way to evaluate these is to plug it into a calc.

7 0
3 years ago
3. Which property of multiplication is shown 1. X = X (a) associative (b) commutative (c) distributive (d) identity​
Agata [3.3K]

Answer:

X = X is <u>Commutative Property of Multiplication</u>.

4 0
3 years ago
Aiden is grocery shopping and wants to know which packages are cheapest. He is
arlik [135]

Answer:Bottle B

Step-by-step explanation:

Given

Bottle A has 175 fluid ounce and cost \$19.25

So it cost \frac{175}{19.25}=9.09\ \text{ounce per}\ \$

Bottle B has 138 fluid ounce and cost \$8.97

So it cost \frac{138}{8.97}=15.38\ \text{ounce per}\ \$

Bottle C has 100 fluid ounce and cost \$8.0

So it cost \frac{100}{8}=12.5\ \text{ounce per}\ \$

Bottle D has 72 fluid ounce and cost \$7.56

So it cost \frac{72}{7.56}=9.52\ \text{ounce per}\ \$

So, Bottle B delivers more ounces at same price

7 0
4 years ago
When the reciprocal of the larger of two consecutive even integers is subtracted from 4 times the reciprocal of the smaller, the
yawa3891 [41]

Answer:  No solution

<u>Step-by-step explanation:</u>

1st number: x

2nd number: x + 2

  • reciprocal of the larger is \frac{1}{x+2}
  • 4 times the reciprocal of the smaller is 4(\frac{1}{x})
  • reciprocal of the larger of two consecutive even integers is subtracted from 4 times the reciprocal of the smaller is 4(\frac{1}{x}) - \frac{1}{x+2}
  • the result is 56: 4(\frac{1}{x}) - \frac{1}{x+2} = 56

Solve the equation:

4(\frac{1}{x}) - \frac{1}{x+2} = 56

\frac{4(x(x + 2))}{x} - \frac{1(x(x + 2))}{x+2} = 56(x(x + 2))

4x + 8 - x = 56x² + 112x

     3x + 8 = 56x² + 112x

             0 = 56x² + 109x - 8

Use the quadratic formula to solve:

x = \frac{-109+/-11\sqrt{113}}{112}

The result is NOT AN INTEGER so there is NO SOLUTION

8 0
3 years ago
Which expression shows the result of applying the distributive property to 9(2+5m) ?
Phantasy [73]

Answer:

c) 18 + 45m

Step-by-step explanation:

9(2+5m)

We multiply the 9 by each term inside the parentheses

9*2 + 9*5m

18+45m

7 0
3 years ago
Read 2 more answers
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