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Ostrovityanka [42]
4 years ago
11

What is the simplest form 3/4 + 2/5

Mathematics
2 answers:
maw [93]4 years ago
7 0

Answer:

1  3/20

Step-by-step explanation:

3/4 + 2/5

Get a common denominator of 20

3/4 *5/5  + 2/5 *4/4

15/20 + 8/20

23/20

20/20 + 3/20

1  3/20

Vinil7 [7]4 years ago
5 0

Answer:

1 and 3/20

Step-by-step explanation:

You want to make the denominators the same so you can answer them:

3/4 = 15/20

2/5 = 8/20

You add 15 and 8, which equals 23.

23/20 = 1 and 3/20.

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USPshnik [31]

The Verdicts on each value of u according to the given inequality are as follows; 11, 13 and 8.

<h3>What values ares solutions to the inequality; u ≤ 13?</h3>

It follows from the task content that the values which are solutions to the inequality; u ≤ 13 are to identified.

To determine the solution of an inequality on a number line, the number line representation of such inequality is very pivotal.

Therefore, the inequality given; u ≤ 13 simply implies that; the solution set of u includes 13 and all numbers to the left of 13 on the number line.

Hence, by considering each of the given values of u; we have;

  • 11 ≤ 13?; Yes.
  • 13 ≤ 13?; Yes.
  • 8 ≤ 13?; Yes.
  • 18 ≤ 13?; No.

Ultimately, the solutions to the inequality among the answer choices are; 11, 13 and 8 respectively.

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hodyreva [135]

Answer:

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Step-by-step explanation:

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3 years ago
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What are the steps used to transform the general form of the equation of a circle to standard form
Bezzdna [24]

Answer:

Step-by-step explanation:

Convert the equation of a circle in general form shown below into standard form. Find the center and radius of the circle. Group the x 's and y 's together. Consider the x2 and x terms only. Complete the square on these terms. Replace the x2 and x terms with a squared bracket.

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Answer:

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Step-by-step explanation:

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The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.10
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The distribution is not a standard normal distribution.

We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.

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E(X) = 0 and V(X) = 1

Given that;

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As such, the distribution is not a standard normal distribution.

Therefore, we can conclude that the distribution is not a standard normal distribution.

Learn more about standard normal distribution here:

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