Answer:
RO
Step-by-step explanation:
Answer:
1. 17,20
2. 40,80
Step-by-step explanation:
1. 5+3=8
8+3=11
11+3=14
14+3=17
17+3=20
pattern is +3
2. 2.5*2=5
5*2=10
10*2=20
20*2=40
40*2=80
pattern is *2
5 girls : 4 boys
5 + 4 = 9 students
= 27 students ( 5girls / 9 students )
*cancel students units*
= 27 ( 5 girls / 9)
= 15 girls
You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.
Answer:
A
Step-by-step explanation:
I just did it
