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Stells [14]
4 years ago
6

Determine the value of (sine of 52 degrees, and 47 minutes). In this case, minutes are 1/60 of a degree.

Mathematics
2 answers:
Lesechka [4]4 years ago
7 0

the answer is d.0.7963540136

Lina20 [59]4 years ago
3 0

Answer:

Option D. 0.7963540136

Step-by-step explanation:

step 1

Convert 52\°\ 47' to degrees

52\°\ 47'=52\°+47/60)=52.7833\°

step 2

Using a calculator

Find the value of sin(52.7833\°)

sin(52.7833\°)=0.7963540136

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Sten invests $3200 in an account earning 2% interest, compounded annually.
Sedaia [141]
I pretty sure your answer is c I may be wrong.
4 0
3 years ago
Please answer this question now
shtirl [24]

Answer:

76 degrees.

Step-by-step explanation:

Let as consider O is the center of the circle . So from the figure it is clear that

\angle AOB=44^{\circ}

\angle COD=118^{\circ}

By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.

We know that, \angle BAD=97^{\circ} and angle BOD is the central angle subtended by arc BD.

\angle BOD=2\times \angle BAD

\angle BOD=2\times 97^{\circ}

\angle BOD=194^{\circ}

Now,

\angle BOD=\angle BOC+\angle COD

194^{\circ}=\angle BOC+118^{\circ}

194^{\circ}-118^{\circ}=\angle BOC

76^{\circ}=\angle BOC

m(arc(BC))=76^{\circ}

Therefore, the measure of arc BC is 76 degrees.

5 0
3 years ago
Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive
PtichkaEL [24]
Looks like the PMF is supposed to be

\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65

Next,

\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25

\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5

\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2
\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5
\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}

If Y=X^2+1, then X^2=Y-1\implies X=\sqrt{Y-1}, where we take the positive root because we know X can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that Y can take on the values 1^2+1=2, 2^2+1=5, and 5^2+1=26. At these values of Y, we would have the same probability as we did for the respective value of X. That is,

\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}

Part (5) is incomplete, so I'll stop here.
8 0
3 years ago
What is the probability of getting this question correct? (Brainliest Answer will be given to the first correct response with a
butalik [34]
If a question has four possible answers, and you are strictly guessing regarding which of them is correct, then the chances of your choosing the correct one from the four is 1 in 4, or 0.25.
4 0
3 years ago
You plan to buy $12,000 in computers at a local chain store. There are two stores located about the same distance from your offi
wariber [46]
Lets calculate the taxes that would been payed at each city:
city1 = 12000(7%) = 12000(0.07) = 840
city2 = <span>12000(8.5%) = 12000(0.085) = 1020
So if you go to city1 instead of city2, you save 1020 - 840 = 180
So you would save $180 from $12000, that is:
 180 out of 12000
= 180/12000
= 0.015
and that is the 1.5%, that is what you could save</span>
4 0
3 years ago
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