312* 17.5= 5460.00
134*19=2546
2546+5460= $8,006.00

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP



Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,





Hence, The 5th term of given AP is 50
that is a lot of answers though
Answer:
14°F
Step-by-step explanation:
We are given that,
The label for the high temperature is -10°C.
It is required to label the alarm in Fahrenheit (°F).
As we know,
(1°C ×
) + 32 = 33.8°F
Thus, for -10°C, we have,
(-10°C ×
) + 32 = -18 + 32 = 14°F
Hence, the Fahrenheit value on the label will be 14°F.