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jenyasd209 [6]
3 years ago
6

One factor of f(x)5x^3+5x^2-170+280 is (x + 7). What are all the roots of the function? Use the Remainder Theorem.

Mathematics
1 answer:
horsena [70]3 years ago
3 0

Answer: (b) x = -7, x = 2, x = 4

<u>Step-by-step explanation:</u>

Remainder Theorem is used to determine if a given value is a root.

It is stated that (x + 7) is a root ⇒ x + 7 = 0  ⇒ x = -7

We can confirm this by plugging in x = -7 and getting a value of 0.

f(x) = 5x³ + 5x² - 170x + 280

f(-7) = 5(-7)³ + 5(-7)² - 170(-7) + 280

      = -1715 + 245 + 1190 + 280

     = 0

CONFIRMED that x = -7 is a zero!

Next, let's try x = 2

f(2) = 5(2)³ + 5(2)² - 170(2) + 280

      = 40 + 20 - 340 + 280

     = 0

CONFIRMED that x = 2 is a zero!

Lastly, let's try x = 4

f(4) = 5(4)³ + 5(4)² - 170(4) + 280

      = 320 + 80 - 680 + 280

     = 0

CONFIRMED that x = 4 is a zero!

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<em>Comment on this answer</em>

Obviously, if one of the quotients is smaller than the other, Camilla can only make as many necklaces as are supported by the constraining resource.

Even if she had 3000 black beads (way more than 2880), she could still only make 96 necklaces (for example) because she would run out of silver beads making that 96th necklace. (There would be 120 black beads left over in that scenario.)

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