$-ax+3b \ \textgreater \ 5\ \ \ |subtract\ 3b\ from\ both\ sides\\\\-ax \ \textgreater \ 5-3b\ \ \ \ |change\ signs\\\\ax \ \textless \ 3b-5\ \ \ \ |divide\ both\ sides\ by\ a \ \textgreater \ 0\\\\\boxed{x \ \textless \ \dfrac{3b-5}{a}}\\\\-ax \ \textgreater \ 5-3b\ \ \ \ |divide\ both\ sides\ by\ (-a)\\\\\boxed{x \ \textless \ \dfrac{5-3b}{-a}\to x \ \textless \ \dfrac{-3b+5}{-a} }$

7 0

4 years ago

Plss help me in this

Alla [95]

Answer: Hello, my name is woods 245. And I'm here to answer your question.

So what do you need with and I will help you with it.

Step-by-step explanation:

8 0

3 years ago

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