Answer: 5
Steps:
5x - 2y = 30
5(8) - 2y = 30
40 - 2y = 30
-2y = 30 - 40
-2y = -10
y = -10/-2
y = 5
I would appreciate the brainliest if this answer was correct and the steps were clear and helpful! :)
Answer:
y=2x-3
Step-by-step explanation:
show work
1=(2*2)+b
1=4+b
1-4=-3
-3=b
check work
y=2x-3
y=(2*2)-3
y=4-3
y=1
<span>Length of outer track = sum of length of 10 pieces = circumference of the outer circle
if R is the Radius of outer circle then...
Circumference of the outer track = 2pi*R
Similarly the circumference of the inner track (with radius r) = 2pi*r
length of each outer piece is 3.4 inch more than length of inner piece
So total outer length is 10*3.4 =34 inches more than the inner length.
=> Outer Circumference - Inner Circumference = 34 inches
=> 2pi*R - 2pi*r = 34
=> 2pi(R -r) = 34
=> R-r = 34/2pi = 5.41 inches
=> R-r = Width of the track = 5.41 inches</span>
The answer is C. Opposite sides have the exact same slope, and the shape is a quadrilateral.
Solution:
As we know reference angle is smallest angle between terminal side and X axis.
As cosine 45 ° is always positive in first and fourth quadrant.
i.e CosФ, Cos (-Ф) or Cos(2π - Ф) have same value.
As, Cos 45°, Cos (-45°) or Cos ( 360° - 45°)= Cos 315°are same.
So, Angles that share the same Cosine value as Cos 45° have same terminal sides will be in Quadrant IV having value Either Cos (-45°) or Cos (315°).
Also, Cos 45° = Sin 45° or Sin 135° i.e terminal side in first Quadrant or second Quadrant.
