By comparing the right triangle ABC with the triangle XYZ, we will see that:
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How to find the given segments?</h3>
So we know that the largest triangle is a dilation of scale factor 2 of the smaller one.
Also, remember that for right triangle we have the relation:
Tan(θ) = (opposite cathetus)/(adjacent cathetus).
Now, the problem tells us that:
tan(x) = 5/2.5
For the angle x, the adjacent cathetus is XY, and the opposite cathetus is YZ.
Then we have:
YZ = 5
XY = 2.5
Knowing that the correspondent sides in the larger triangle will be 2 times the above ones, we can see that:
AC = 2*XY = 2*2.5 = 5
CB = 2*YZ = 2*5 = 10
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
I will assume that is 19 2/5 INCHES.Set up a proportion with the actual height of the building.19.4 / h = 1/75Now, for cross-multiplying:H = 75 x 19.4 = 1455 feet.<span>That's a tall building!!!</span>
(42)^3 -(24)^3 - (18)^3
= (74,088)-(13,824)-(5,832)
= 54,432