Answer:
The diameter of the bacterium is 4.05 times the diameter of the plant cell
Step-by-step explanation:
The given parameters both represent diameters
Plant Cell P = 1.26m
Bacterium B = 5.1m
First write out both expressions:
P = 1.26
B = 5.1
Divide B by P
5.1 / 1.26 = 4.04762 Round to 4.05
Multiply both side by P
P * B/P = 4.05 P
B = 4.05 P
This shows that the diameter of the bacterium is 4.048 times the diameter of the plant cell.
Let
Vco------------------- >Volume cone
Vcy------------------ >Volume cylinder
r= 8mm
hco----------- > height of cone=18 mm
hcy------------ > height of cylinder =54-18=36 mm
then
Vco=π*r² *hco/3--------- > π*8² *18/3=π*384 mm³
Vcy=π*r² *hcy--------- > π*8² *36=π*2304 mm³
the total cubic millimeters of sand=Vco+Vcy=π*384+π*2304=π*2688
if 10π cubic millimeters --------------------- > 1 seg
π*2688--------------------------------- X
X=π*2688/10π=268.8 seg
the answer is 268.8 seg
It would be letter. b....
The answer will be <span>sin<span>(<span>−1</span>)</span></span>−32<span>=<span>−<span>32.841471 Im not sure but thats what i think</span></span></span>
