Well you know that you have to balance out the equation to 0. So if I is -1 and Ca is +2 you know that I had to equal to -2. So you can do that by having two of them. So Ca=+2 and I2=-2 so CaI2 would equal 0 meaning that would be the correct answer. Hope that I explained that correct :)
Helloo
To convert to L
2.5 hm^3 * (100m/hm)^3 *1000 L/m^3 gives a volume of 2.5*10^9 L
Have a nice day
Answer:
41.3 °C
Explanation:
From the question given above, the following data were obtained:
Mass (M) of water = 27.56 g
Heat (Q) loss = 2443 J
Final temperature (T2) = 62.5 °C
Initial temperature (T1) =?
NOTE: The specific heat capacity (C) of water is 4.18 J/g°C
Thus, we can obtain the initial temperature of the water by using the following formula:
Q = MC(T2 – T1)
2443 = 27.56 × 4.18 (62.5 – T1)
2443 = 115.2008 (62.5 – T1)
Divide both side by 115.2008
2443 / 115.2008 = (62.5 – T1)
21.20645 = 62.5 – T1
Collect like terms
21.20645 – 62.5 = – T1
– 41.3 = – T1
Divide both side by – 1
– 41.3 /– 1= – T1 / –1
41.3 = T1
T1 = 41.3 °C
Thus, the initial temperature of the water was 41.3 °C
