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Anastaziya [24]
3 years ago
5

Why is it reasonable to assume the specific heats of naoh and hcl solutions are the same as water?

Chemistry
1 answer:
ivolga24 [154]3 years ago
7 0
It would be reasonable to assume that the specific heats of NaOH and HCl solutions are the same as water given that the concentration of these solutions are low about 1 M or less.  Having low concentrations would mean that there is only small amount of particles of HCl or NaOH in the solution so most of the properties of the solution is the same as that of a pure water since less particles can interfere with any process. Specific heat is the amount of heat energy needed per mass in order to be able to raise the temperature by a degree. So, when these particles are present in small amount, it is only the water that would determine the amount of heat needed.
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Write the ions present in a solution of na3po4. express your answers as chemical formulas separated by a comma. offset subscript
dexar [7]
Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:

(Na)_{3}(PO_{4}) ==> 3 Na^{+}   +  PO_{4} ^{3-}
5 0
3 years ago
The radius of an indium atom is 0.163 nm. If indium crystallizes in a face-centered unit cell, what is the length of an edge of
adoni [48]

<u>Answer:</u> The edge length of the unit cell is 0.461 nm

<u>Explanation:</u>

We are given:

Atomic radius of iridium = 0.163 nm

To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

a=2\sqrt{2}R

Putting values in above equation, we get:

a=2\sqrt{2}\times 0.163=0.461nm

Hence, the edge length of the unit cell is 0.461 nm

8 0
3 years ago
How many moles are represented by 3.01 x10^24 oxygen atoms?
asambeis [7]
<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u> </u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})
  2. Multiply/Divide:                \displaystyle 4.99834 \ mol \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

4.99834 mol O₂ ≈ 5.00 mol O₂

4 0
3 years ago
Nitrogen forms a surprising number of compounds with oxygen. A number of these, often given the collective symbol NOx (for "nitr
kvv77 [185]

Answer:

9.2

Explanation:

Let's do an equilibrium chart of this reaction:

2NO(g) + O₂(g) ⇄ 2NO₂(g)

4.9 atm    5.1 atm    0       Initial

-2x             -x           +2x    Reacts (stoichiometry is 2:1:2)

4.9-2x      5.1-x        2x      Equilibrium

The mole fraction of NO₂ (y) can be calculated by the Raoult's law, that states that the mole fraction is the partial pressure divided by the total pressure:

y = 2x/(4.9 - 2x + 5.1 -x + 2x)

0.52 = 2x/(10 - x)

2x = 5.2 -0.52x

2.52x = 5.2

x = 2.06 atm

Thus, the partial pressure at equilibrium are:

pNO = 4.9 -2*2.06 = 0.78 atm

pO₂ = 5.1 - 2.06 = 3.04 atm

pNO₂ = 2*2.06 = 4.12 atm

Thus, the pressure equilibrium constant Kp is:

Kp = [(pNO₂)²]/[(pNO)²*(pO₂)]

Kp = [(4.12)²]/[(0.78)²*3.04]

Kp = [16.9744]/[1.849536]

Kp = 9.2

4 0
3 years ago
why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis
Helga [31]

<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

  • Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

<u>Current uses of plasmas:</u>

  • First, it is used to make semiconductors for different types of electronic equipment
  • Secondly, they're used in making transmitters for high-temperature films.

<u>Way scientists and engineers hope to use plasmas in the future:</u>

  • The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0
3 years ago
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