Question

2x2-9x+1=0 value of discrimination and number of real solutions

Answer 1

$2 \times 2 - 9x + 1 = 0 \\ \\ 1. \: - 9x + 5 = 0 \\ 2. \: - 9x = - 5 \\ 3. \: \frac{ - 9x}{ - 9} = \frac{ - 5}{ - 9} \\ x = \frac{5}{9} \\ or \\ \\ 1. \: 4 - 9x + 1 = 0 \\ 2. \: - 9x + 5 = 0 \\ 3. \: - 9x = - 5 \\ 4. \: x = \frac{ - 5}{ - 9} \\ 5. \: x = \frac{5}{9}$