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2 years ago

2x2-9x+1=0 value of discrimination and number of real solutions

1 answer:

5 0

$2 \times 2 - 9x + 1 = 0 \\ \\ 1. \: - 9x + 5 = 0 \\ 2. \: - 9x = - 5 \\ 3. \: \frac{ - 9x}{ - 9} = \frac{ - 5}{ - 9} \\ x = \frac{5}{9} \\ or \\ \\ 1. \: 4 - 9x + 1 = 0 \\ 2. \: - 9x + 5 = 0 \\ 3. \: - 9x = - 5 \\ 4. \: x = \frac{ - 5}{ - 9} \\ 5. \: x = \frac{5}{9}$

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Convert the expression (5x + 2)(x - 7) from factored form to standard form

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We use the FOIL method here. First, Outer, Inner, and Last.

(5x)(x) = 5x^2

(5x)(-7) = -35x

(2)(x) = 2x

(2)(-7) = -14

5x^2 - 35x + 2x - 14

Now combine like terms.

5x^2 - 33x - 14.

This is the right answer because it is now in the form of ax^2 + bx + c

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Vitek1552 [10]

4 times
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uysha [10]

Answer:

$\boxed{\sf Option \ 4}$

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Subtract x from both sides.

$\sqrt{2x-3} +x-x=-x+3$

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Square both sides.

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Subtract x²-6x+9 from both sides.

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Factor left side of the equation.

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Set factors equal to 0.

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Check if the solutions are extraneous or not.

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Plug x as 6.

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3 years ago

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Ira Lisetskai [31]

Answer:

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