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2 years ago

14

2x2-9x+1=0 value of discrimination and number of real solutions

1 answer:

Afina-wow [57]2 years ago

5 0

$2 \times 2 - 9x + 1 = 0 \\ \\ 1. \: - 9x + 5 = 0 \\ 2. \: - 9x = - 5 \\ 3. \: \frac{ - 9x}{ - 9} = \frac{ - 5}{ - 9} \\ x = \frac{5}{9} \\ or \\ \\ 1. \: 4 - 9x + 1 = 0 \\ 2. \: - 9x + 5 = 0 \\ 3. \: - 9x = - 5 \\ 4. \: x = \frac{ - 5}{ - 9} \\ 5. \: x = \frac{5}{9}$

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Answer:

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