(05.01)

Mathematics

2 answers:

Irina18 [472]3 years ago

6 0

I hope this helps you

Anna71 [15]3 years ago

4 0

Simplify completely quantity 3 x squared plus 21 x minus 54 all over x squared plus 3 x minus 54.

quantity 3 x squared plus 21 x
(3x^2 + 21x - 54)

x squared plus 3 x minus 54.
(x^2 + 3x -54)

(3x^2 + 21x - 54)/(x^2 + 3x -54)

(3(x+9)(x-2)) / ((x+9)(x-6)

3(x-2) / (x-6)

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Need help pls! Answer asap

Lostsunrise [7]

1. 130°

I don't remember too many specifics from my past math classes, but I always remembered this because that is an upside-down mirror of the 130° angle.

2. 50°

A straight line is 180°, and 180 - 130 = 50.

7 0

3 years ago

Read 2 more answers

Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they

inysia [295]

You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):

5x + 10y = 725
x + y = 100

By substitution, we get:

5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
-5x = 725 - 1000
-5x = -275
x = -275/-5 = 55

100 - 55 = 45

Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.

To verify, plug and chug the results back into the original equations:

5(55) + 10(45) = 725
275 + 450 = 725
725 = 725 [OK]

55 + 45 = 100 [OK]

4 0

3 years ago

Write the following expression in standered form. -3•2•a+5(-7b)+(12•c•4)

Alex

Answer:

−6a − 35b + 48c

Step-by-step explanation:

You do pemdas and if you know Pemads you will get your anwser

6 0

2 years ago

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .