Circumference = pi * diameter, in this case you have:
c=8p in
The square root of any number is the same as that number to the 1/2 power
root(b)=b^(1/2)
Are you looking for
2 <|= 2x-4 <|= 10 ? <|= is less than or equal to
my answer 3 <|= x <|= 7
Answer:
This is the “best” method whenever the quadratic equation only contains x2 terms.
The general approach is to collect all x2 terms on one side of the equation while keeping the constants to the opposite side.
step by step: but in order to solve a quadratic using the square root principle the problem must be in the correct form. To solve a quadratic using the square root principle the quadratic must be in vertex form, a(x – h)2 + k.
