___________________________
◆ AREA RELATED TO CIRCLES ◆ ___________________________
As shown in the figure ,
Radius of circle = 5 cm
Side of square = 2 × (Radius of inscribed circle)
Side of square = 2 × 5 cm
Side of square = 10 cm = a
___________________________
Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )
Area of shaded region =
Area of shaded region =
Area of shaded region = 100 - 78.571
Answer:
Step-by-step explanation:
Answer E is the only one that is close
<h3><u>Solution: </u></h3>
Radius of Cylindrical Pillar , r = 28 Cm = 0.28 m.
Curved surface area of a Cylindrical = 2πrh.
Curved surface area of a pillar -
Curved surface area of 24 such Pillar :-
(7.04 x 24 = 168.96m²)..
- Cost of painting an area of 1 m² = Rs8...
• Therefore , cost of painting 1689.6m² :-
( 168.96 x 8 = Rs 1351.68)...
Independent: number of hours worked
Dependent: income earned
Domain: between 0 and 40 hours
Range: between 0 and 480$
22 True For all real Numbers A and B, A - B = -B + A
23 True For all real Numbers P, Q, and R, P - Q - R = P - R - Q
24) True For all real Numbers X, Y, Z and (X + Y ) + Z = Z + (X + Y)
25) False For all real Numbers M and N, M/M * N = N/N ==> Example: 5/5 * 3 ≠ 3/3 * 5
26) Examples:
Counterexamples =====> 5 - 0 = 5; 5/1 = 5
5 - 3 ≠ 3 - 5; (5 - 3 ) - 2 ≠ 5 - (3 - 2 );
6/3 ≠ 3/6; (24/6 )/2 ≠ 24/ (6/ 2 )
Hope that helps!!!! : )