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Anettt [7]
3 years ago
9

What is the solution to the system of equations graphed below? (2,0)

Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

can see the question try to resubmit for me pls

Step-by-step explanation:

ty

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Can someone please help me I posted this multiple times but no one answers pls help me quick​
mario62 [17]
You would have to make 465=1550-7 1/2 x and find x
Subtract 1550 from both sides
-1085=-7 1/2x
Divide -7 1/2 on both sides
And the answer is 144 2/3
Sorry about ur bad luck
6 0
2 years ago
Wats 10 to the 2nd power divied by 5 to the 2nd power
Ilya [14]

Answer:

4

Step-by-step explanation:

10^2/5^2

Do the exponents first

10 to the 2nd power is 100

5 to the 2nd power is 25

100/25

100 divided by 25 is 4

So the answer is 4

Hope this helps!

6 0
3 years ago
Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√
TiliK225 [7]
Parameterize the part of the sphere by

\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)

with 0\le u\le2\pi and 0\le v\le\dfrac\pi4. Then

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv

So the area of S (the part of the sphere above the cone) is given by

\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi
4 0
4 years ago
A go-karts top speed is 607,200 feet per hour. what is the speed in miles per hour?
Genrish500 [490]

Answer:115 miles/hour

Step-by-step explanation: one mile equals to 5280 feet, so 607200 divided into 5280 is 115 and as your timing don’t change you can convert only the distance

7 0
3 years ago
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
3 years ago
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