3 years ago

Find 121 square by repeated subtraction

Mathematics

1 answer:

egoroff_w [7]3 years ago

5 0

Answer:

121 – 1 = 120. 120 – 3 = 117.

Step-by-step explanation:

You might be interested in

Is 9x to the power of 2 and 5x like terms ?

ArbitrLikvidat [17]

9x^2 and 5x are not like terms because 9x is being squared and 5x isn't.

8 0

3 years ago

Read 2 more answers

By selling a laptop at $1,000 for which consumers are willing to pay up to $1,200, a consumer electronics firm makes a profit of

mr Goodwill [35]

Answer:

600

Step-by-step explanation:

7 0

3 years ago

biked 4 ½ miles today, and biked 6 ¾ miles. How many times further did bike compared to ’ ride? SHOW YOUR WORK.

Tresset [83]

Answer: 2 1/4

Step-by-step explanation: first off change the 1/2 to 2/4. then subtract 6 3/4 to 4 2/4. which gives you 2 1/4

5 0

3 years ago

Read 2 more answers

Is this correct now?

Makovka662 [10]

I would say no it’s not correct, the point is not in the correct place

8 0

3 years ago

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

Ratling [72]

we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

$30a^{2+k}b^{4}$

now, we can equate it with right side

and we get

$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

and they are equal

so, exponent of a must also be equal

$2+k=6$

now, we can solve for k

$2+k-2=6-2$

$k=4$ ................Answer

3 0

4 years ago

Read 2 more answers

Find 121 square by repeated subtraction​

Find 121 square by repeated subtraction