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Tems11 [23]
3 years ago
6

Please help me out , Currently stuck on this problem

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0

Answer: it will be 3.7 cuz its perpendicular

have a good day,     hey thechesguy nice name and the guy under copied from me.

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Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
Let x △ y be defined by x △ y=x−5y. What is the value of 3 △  (−4)
TEA [102]

x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23

5 0
3 years ago
Can someone help please
Svetach [21]
I believe it would be d. equilateral. becuz a equilateral triangle is a triangle with 3 equal sides, and 3 equal angles.
7 0
2 years ago
What is the solution to the linear equation d-10-2d+7=8+d-10-3d
bija089 [108]
D-10-2d+7 = 8 + d- 10 -3d
d-2d-10+7 = 8-10 +d -3d
-d-3=-2-2d
-d+2d=3-2
d=1

Final answer: C. d=1
8 0
3 years ago
Read 2 more answers
A chord is 10cm from the centre of a circle of radius 15cm. Find the length of the chord.
almond37 [142]

Answer: 21.44 cm

Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

From the figure, the length of the chord is AC

Applying Pythagoras

\Rightarrow AO^2=OB^2+AB^2\\\Rightarrow AB^2=15^2-10^2\\\Rightarrow AB^2=225-100=115\\\Rightarrow AB=\sqrt{115}=10.72\ cm

The length of the chord is AC=2AB=21.44\ cm

5 0
3 years ago
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