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timama [110]
3 years ago
5

Is Time a function of temperature?

Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

In general, time is not a function of temperature, but this could depend on the problem you're solving. For example, imagine a ball of metal cooling down, and data was given on how long the ball was cooling down and the temperature at the center. Someone could have fit a curve or function to the temperature to show how much time has elapsed when inputting temperature as the independent variable.

Step-by-step explanation:

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If f(x)=sinx−1/cos2x, then limx→π2f(x) is equivalent to which of the following?
Harrizon [31]

Answer:

2

Step-by-step explanation:

Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2

Substituting π/2 into the function

lim x-->π/2 sin(x)-1/cos 2(x)

= sin(π/2) - 1/cos(2)(π/2)

= 1 - 1/cosπ

= 1- 1/-1

= 1 -(-1)

= 1+1

= 2

Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2

8 0
3 years ago
A grocery store sells a bag of 8 oranges for $6.80. How much does one orange cost?
Vladimir79 [104]

Answer:

A 6 lb bag of another brand

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
7-9: Practice Buddy: Independent Practice; Problem Solving please help!
strojnjashka [21]

Answer:

4/3/8

Step-by-step explanation:

12/1/2-8/8/1

=25/2-65/8

=100-65/8

=35/8

=4/3/8

3 0
3 years ago
Read 2 more answers
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0
3 years ago
⚠️⚠️⚠️help⚠️⚠️⚠️⚠️⚠️​
Naddika [18.5K]
The second one should be the answer
7 0
3 years ago
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