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3 years ago

9

Marlon took a total of 12 pages of notes during 3 hours of class. After attending 4 hours of class, how many total pages of note

s will Marlon have in his notebook? Assume the relationship is directly proportional.

1 answer:

elena-14-01-66 [18.8K]3 years ago

5 0

I think it’s 28 I’m not sure

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A tanker of capacity 200 litres has 12.05 litres of oil. how much more oil can be poured into the tanker ?

Scilla [17]

Answer:

187.95 liters.

Step-by-step explanation:

the entire capacity of the tank is 200 liter, you subtract how much oil is in there already, you will have the remaining Of the capacity that can be added.

200 - 12.05 = 187.95

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3 years ago

Jennifer can clean her room 2 hours, while John can clean the same room in 5 hours. How many hours would it take for them to cle

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For 1 hour:
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- John cal clean 1/5 of her room.
Both can clean: 1/2 + 1/5 = 5/10 + 2/10 = 7/10
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x hours---------- 1
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3 years ago

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You are considering the purchase of a closed circuit TV monitoring system for your store. The quarterly physical inventory has s

Tcecarenko [31]

If quarterly shrinkage (every 3 months) is 2.5%, then multiplying by $875,495 gives a value of 21887.38, or an average monthly shrinkage of 21887.38 / 3 = $7,295.79.For an employee to monitor the CCTV, it would cost ($7.5/h)(11 h/d)(30 d/m) = $2,475/month. Therefore, it is much cheaper (around 2/3 cheaper) to have an employee monitor CCTV rather than to allow the high shrinkage rate.

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3 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

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3 years ago

Solve:<br> I kept trying but I can’t do it <br> Thank you a lot for you help

scoray [572]

Answer:

5.25

Step-by-step explanation:

15/10=1.5

9*1.5=13.5

13.5-3=10.5

10.5/2=5.25

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3 years ago

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