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dimaraw [331]
3 years ago
11

You are considering the purchase of a closed circuit TV monitoring system for your store. The quarterly physical inventory has s

hown inventory shrinkage to be 2.5%. Sales for the period were $875,495. The store is open 11 hours a day, 7 days a week. You estimate that you will have to pay an employee $7.50 per hour to monitor the system. Compare the monthly cost of monitoring the closed circuit TV system to monthly shrinkage. Assume 30 days per month.
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0
If quarterly shrinkage (every 3 months) is 2.5%, then multiplying by $875,495 gives a value of 21887.38, or an average monthly shrinkage of 21887.38 / 3 = $7,295.79.For an employee to monitor the CCTV, it would cost ($7.5/h)(11 h/d)(30 d/m) = $2,475/month. Therefore, it is much cheaper (around 2/3 cheaper) to have an employee monitor CCTV rather than to allow the high shrinkage rate.

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Answer:

Step-by-step explanation:

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Number of days spent to read = x

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For slope = 1.25 means "1.25 pages read per day"

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3 0
2 years ago
REPOST!!!!!! 20 POINTS!!!!!!
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Answer:

A

Step-by-step explanation:

according to tangent property

we get

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  • BK=CK

Given that

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Thus our equation is

\rm \displaystyle 2AM + 2AN + 2BK = 34

substitute the given values

\rm \displaystyle 2.6+ 2AN+ 2.4 = 34

simplify multiplication:

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simplify addition:

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cancel 20 from both sides:

\rm \displaystyle 2AN=14

divide both sides by 2:

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therefore our answer is A

6 0
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Answer:

Infinite Solutions.

Step-by-step explanation:

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The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
Savatey [412]
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
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k-4=0
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k=-6 or 4

64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7



so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
3 0
3 years ago
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