Answer:
x = - ![\frac{57}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B57%7D%7B5%7D)
Step-by-step explanation:
(x - 3) - 5 =
(x - 1)
Multiply through by 8 to clear the fractions
6(x - 3) - 40 = x - 1 ← distribute parenthesis and simplify left side
6x - 18 - 40 = x - 1
6x - 58 = x - 1 ( subtract x from both sides )
5x - 58 = - 1 ( add 58 to both sides )
5x = - 57 ( divide both sides by 5 )
x = - ![\frac{57}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B57%7D%7B5%7D)
Answer:
12.247 Hope I helped
Step-by-step explanation:
![\sqrt{54}+\sqrt{24} \\7.348+4.899\\12.247](https://tex.z-dn.net/?f=%5Csqrt%7B54%7D%2B%5Csqrt%7B24%7D%20%20%5C%5C7.348%2B4.899%5C%5C12.247)
Answer:
T=4
Step-by-step explanation:
it is just half of what the other side is if one side is like 1 1/2 then you just break the other side in half and that will give you T.
This can be solved in two ways: With heavy tools or with just algebra.
What is your level? Have you studied calculus?
With pure algebra:
We need to find the maximum of the function <span>h = −16t^2 + 36t + 5
Lets take out -1 for simplicity:
</span><span>h = −(16t2 - 36t - 5)
For now lets just work with this: </span>16t^2 - 36t - 5
16t^2=(4t)^2
(4t-x)^2= 16t^2-2*4xt+x^2
we have -36t so x should be 4.5 as 2*4*4.5=36
Lets see what we have now:
16t^2 - 36t - 5= (4t-4.5)^2 is this true? No but close
(4t-4.5)^2= 16t^2- 2*4*4.5t +4.5^2= 16t^2-36t+20.25
16t^2 - 36t - 5 and 16t^2-36t+20.25 nearl the same just take away 25.25 from the right hand side
Getting long, just stay with me:
16t^2 - 36t - 5= (4t-4.5)^2 - 25.25
h= -{(4t-4.5)^2 -25.25}
h=-(4t-4.5)^2 + 25.25
We want to find the maximum of this function. -(4t-4.5)^2 this bit is always negative or 0, so it maximum is when it is 0. Solve: 4t-4.5=0
t=1,125
The P point (-6,4) and the Q point is (1,4). Both of the y-coordinates are 4 so the answer is B.