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vladimir1956 [14]
2 years ago
15

Which graph represents the function? f(x)=1x−1−2 IS MY ANSWER CORRECT????

Mathematics
1 answer:
7nadin3 [17]2 years ago
7 0
Yes your answer is right
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Help!!!!! stuck on this
8090 [49]
I hope this helps you




Pythagorean



hypothenus ^2=base^2+height ^2



hypothenus ^2=15^2+20^2



hypothenus ^2=225+400



hypothenus ^2=625



hypothenus ^2=25
7 0
3 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
What are two or more geometric figures that are identical in shape although not necessarily the same size?
Andrei [34K]

Unless I am misreading, the question, or don't know all of it, there can be an infinite number of similar shapes. Three are give to you at the bottom of this answer, but there are many more possibilities.

3 0
3 years ago
Nter the equation of the line in slope-intercept form.<br><br> Slope is 6, and (1, 3)
kupik [55]

Answer:

The equation in the slope-intercept form will be:

y=6x-3

Step-by-step explanation:

Given

  • slope = m = 6
  • point = (1, 3)

As we know that the equation of a line in point-slope form is

y-y_1=m\left(x-x_1\right)

substituting the values m = 6 and point = (1, 3)

y-3=6\left(x-1\right)

Writing the equation in slope-intercept form

y=mx+b

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

y-3=6\left(x-1\right)

add 3 to both sides

y-3+3=6\left(x-1\right)+3

y=6x-3

Therefore, the equation in the slope-intercept form will be:

y=6x-3

6 0
3 years ago
Given the system of equations:
uranmaximum [27]

Answer:

x=4

y=2

Step-by-step explanation:

2x+2y=12

x−y=2

​In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+2y=12,x−y=2

To make 2x and x equal, multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 2.

2x+2y=12,2x+2(−1)y=2×2

Simplify.

2x+2y=12,2x−2y=4

Subtract 2x−2y=4 from 2x+2y=12 by subtracting like terms on each side of the equal sign.

2x−2x+2y+2y=12−4

Add 2x to −2x. Terms 2x and −2x cancel out, leaving an equation with only one variable that can be solved.

2y+2y=12−4

Add 2y to 2y.

4y=12−4

Add 12 to −4.

4y=8

Divide both sides by 4.

y=2

Substitute 2 for y in x−y=2. Because the resulting equation contains only one variable, you can solve for x directly.

x−2=2

Add 2 to both sides of the equation.

x=4

The system is now solved.

x=4,y=2

Correct choice is B) x=4.

8 0
2 years ago
Read 2 more answers
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