Question

Cylinder A has a radius of 8 inches and height of 3 inches. cylinder B has a volume of 96n. what is the percent change in volume between cylinders A and B?
A.) cylinder B is 50% smaller than cylinder A


B.) cylinder B is 75% smaller than cylinder A.


C.) cylinder B is 150% bigger than cylinder A.


D.) cylinder B is 200% bigger than cylinder A.

Answer 1

Answer:

A.) cylinder B is 50% smaller than cylinder A

Step-by-step explanation:

Took the test

Answer 2

Answer:

A.) cylinder B is 50% smaller than cylinder A

Step-by-step explanation:

The volume of cylinder A: $V_{A}=\pi r^2h$

Where $r$ is the radius: $r=8in$

and $h$ is the height:  $h=3in$

$V_{A}=\pi (8)^2(3)$

$V_{A}=(64)(3)\pi$

$V_{A}=192\pi$

and the volume of cylinder B according to the problem:

$V_{B}=96\pi$

Because $96\pi$ is half of $192\pi$, we can say that cylinder B has half the volume of cylinder A, in other words:

cylinder B is 50% smaller than cylinder A

Which is option A.