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2 years ago

PLEASE HELP!!! TIMED QUESTION!!! NOT A TEST NOR QUIZ!!!!

Mathematics

1 answer:

natita [175]2 years ago

8 0

Answer:

LCD=280

Step-by-step explanation:

Equivalent Fractions with the LCD

1/8 = 35/280

2/7 = 80/280

4/5 = 224/280

Solution:

Rewriting input as fractions if necessary: 1/8, 2/7, 4/5

For the denominators (8, 7, 5) the least common multiple (LCM) is 280.

LCM(8, 7, 5)

Therefore, the least common denominator (LCD) is 280.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

1/8 = 1/8 × 35/35 = 35/280

2/7 = 2/7 × 40/40 = 80/280

4/5 = 4/5 × 56/56 = 224/280

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P and q are integers that are multiple of 5. Which of this

zhuklara [117]

Answer:

we conclude that the only option (a) is true.

Step-by-step explanation:

As we know that the multiples of 5 are the numbers which we get when we multiply by 5.

i.e.

5×1=5

5×2=10

Here, 5 and 10 are multiples of 5.

Let p and q are integers that are multiples of 5.

Let us consider

p=5

q=10

p+q=5+10

= 15

A number is divisible by 5 if it ends in 5 or 0.

i.e. 15/5 = 3

so p+q is divisible by 3 as there is no remainder left.

Therefore, option (a) is true.

Checking the other options:

(b) P –q is divisible by 10

p=5

q=10

p-q=5-10

= -5

Numbers that are divisible by 10 need to be even or divisible by 2 and divisible by 5.

As -5 is not divisible by 2.

So, option b is NOT true.

(c) P +q is divisible by 20

p=5

q=10

p-q=5+10

= 15

Divisibility rule of 20 implies that the last two digits of the number are either 00 or divisible by 20 .

Therefore, P + q= 20 is not divisible by 20 as we don't get the whole number.

(d) P + q is divisible by 25

p=5

q=10

p-q=5+10

= 15

p+q=15 is not divisible by 25 as it does not end with 00, 25, 50, or 75.

so, option d is NOT correct.

Therefore, we conclude that the only option (a) is true.

5 0

2 years ago

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

2 years ago

Question 1

Ivenika [448]

Answer:

66.125

Step-by-step explanation:

5 0

3 years ago

For the function y = 3x^2 - 12x + 4, what is the mirror point for the y-intercept? Give your answer in (x,y) point form.

saveliy_v [14]

Answer:

Your in Pacyber aren't you? Mr. Breux class? Anyway the answer is (0,-4)

Step-by-step explanation:

The y intercept is (0,-4)

6 0

2 years ago

An ostrich can run 25 miles in 40 minutes. How many minutes will it take the ostrich to run 40 miles if it runs at the same spee

fenix001 [56]

The Ostrich will take 64 minutes to cover 40 miles.

Data;

rate = 25 miles in 40 minute

To calculate the time it will take the ostrich to cover 40 miles, we have to compare it with the rate (speed).

$25mi = 40 min\\40 mi = x min$

Cross multiply both sides

$x * 25 =40 * 40$

simplify the value

$x*25=40*40\\25x = 1600\\$

divide both sides by the coefficient of x

$25x = 1600\\25x/25 = 1600/25\\x = 64$

From the calculations above, it would take the ostrich 64 minutes to cover 40 miles.

Learn more on rates here;

brainly.com/question/8728504

6 0

2 years ago