First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
The missing interior angle, x, of the convex polygon is 168⁰.
<h3>
Sum of interior angles of convex polygon</h3>
The sum of interior angles of a convex polygon is calculated as follows;
S = (n - 2) 180
S = (8 - 2) 180
S = (6) 180
S = 1080
The missing interior angle, x, is calculated as follows;
x + 126 + 146 + 130 + 140 + 146 + 134 + 90 = 1080
x + 912 = 1080
x = 1080 - 912
x = 168⁰
Learn more about interior angles of polygon here: brainly.com/question/24966296
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