Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4
8x-5=-3(3-2x) Sole for x
2 answers:
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Answer:
The following Triangles are Right Triangles:
1. Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
Step-by-step explanation:
For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.
i.e.
For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
AC² = 365² = 133225
AB² + BC² = 76² + 357² = 1333225
∴ AC² = AB² + BC²
Hence Δ ABC a Right Triangle.
For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
MT² = 845² = 71405
MI² + IT² = 123² + 836² = 714025
∴ MT² = MI² + IT²
Hence Δ MIT a Right Triangle.
For Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
ML² = 101² = 10201
ME² + EL² = 20² + 99² = 10201
∴ ML² = ME² + EL²
Hence Δ MEL a Right Triangle.
Using the binomial distribution, it is found that:
a) There is a 0.0501 = 5.01% probability that you need to contact four people.
b) You expect to contact 1.82 students until you find one who lives within five miles of you.
c) The standard deviation is of 1.22 students.
d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.
e) It is expected that 2.75 students live within five miles of you.
For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 55% of the students live within five miles of you, thus
.
Item a:
This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:
0.0501 = 5.01% probability that you need to contact four people.
Item b:
The expected number of trials in the binomial distribution until q successes is given by:
In this problem, , and 1 trial, thus
, hence:
You expect to contact 1.82 students until you find one who lives within five miles of you.
Item c:
The standard deviation of the number of trials until q successes are found is given by:
Hence, since :
The standard deviation is of 1.22 students.
Item d:
This probability is when
, hence:
There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.
Item e:
The expected value of the binomial distribution is:
Hence, since :
It is expected that 2.75 students live within five miles of you.
A similar problem is given at brainly.com/question/25343741