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Evgen [1.6K]
3 years ago
13

Find the value of x and the length of each side—- geometry

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

I think x = 7

but I'm not sure

.. :-))

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The graph shows the distance, y, that a car traveled in x hours:
vesna_86 [32]
Here, You need to calculate the slope of the graph by taking any two random points, as follows:
(x₁,y₁) = (0,0) & (x₂,y₂) = (1,55)

Now, we know, 
y₂-y₁ = m(x₂-x₁)
55-0 = m(1-0)
m = 55/1
m = 55

Here m represents the slope of graph which is nothing but rate of change of distance.

In short, option A will be your answer.

Hope this helps!
7 0
4 years ago
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A tire maker produces 20000 tires to be shipped. they inspect 200 of the tires and find that 16 or defective. how many tires of
Xelga [282]

\frac{16}{200}  =  \frac{2}{25}
is the proportion of tires that are defective so
\frac{2}{25}  \times 20000 = 1600
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3 years ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0
3 years ago
HELP ANSWER ASAP PLS Given the following diagram, find the trigonometric ratios.
saveliy_v [14]

Answer:

sin B = 15/17

Cos B = 8/17

Tan B = 15/8

Step-by-step explanation:

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3 years ago
What is the value of the expression 7- x when x =2.
Schach [20]

Answer:

5 is the answer of the equation

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